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6.2. Equilibrium - II (icon Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.2. Equilibrium - II (icon Equilibrium)1 Mark
MCQ
If $pK_b$ of a base is $5$, then $K_a$ of its conjugate acid will be
  • A
    $10^5$
  • B
    $10^{-5}$
  • ✓
    $10^{-9}$
  • D
    $10^{-14}$
✓

Answer

Correct option: C.
$10^{-9}$
c
$\mathrm{pk}_{\mathrm{a}}+\mathrm{pk}_{\mathrm{b}}=14$ (for conjugate pairs)

$\mathrm{pl} \mathrm{k}_{\mathrm{a}}=14-\mathrm{pk}_{\mathrm{b}}=14-5=9$

$\mathrm{ka}=10^{-\mathrm{pk_a}}=10^{-9}$

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