If Poission's ratio $\sigma $ is $ - \frac{1}{2}$ for a material, then the material is
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(a) $\frac{{dV}}{V} = (1 + 2\sigma )\frac{{dL}}{{dL}}$
if $\sigma = - \frac{1}{2}$ then $\frac{{dV}}{V} = 0 $ i.e. $K = \infty$
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