Question
If S and T are two sets such that S has 21 elements T has 32 elements and$S \cap T$has 11 elements, how many elements does$S \cup T$have?

Answer

Here n(S) = 21, n(T) = 32 and$n(S \cap T) = 11$

We know that$n(S \cup T) = n(S) + n(T) - n(S \cap T)$

$\therefore n(S \cup T) = 21 + 32 - 11 = 42.$

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