MCQ
If ${\sin ^{ - 1}}\frac{1}{2} = {\tan ^{ - 1}}x,$ then $ x =$
  • A
    $\sqrt 3 $
  • $\frac{1}{{\sqrt 3 }}$
  • C
    $\frac{1}{{\sqrt 2 }}$
  • D
    None of these

Answer

Correct option: B.
$\frac{1}{{\sqrt 3 }}$
b
(b) Given that ${\sin ^{ - 1}}\frac{1}{2} = {\tan ^{ - 1}}x$

$ \Rightarrow \,\,{\tan ^{ - 1}}x = \frac{\pi }{6}$

$ \Rightarrow \,\,x = \tan {30^o} = \frac{1}{{\sqrt 3 }}$.

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