MCQ
If $\sin ^{-1} \frac{1}{2}=\tan ^{-1} x$, then $x=$
  • A
    $(\sqrt{3})$
  • $\frac{1}{\sqrt{3}}$
  • C
    $\frac{1}{\sqrt{2}}$
  • D
    $(-\sqrt{3})$

Answer

Correct option: B.
$\frac{1}{\sqrt{3}}$
(B) $\sin ^{-1} \frac{1}{2}=\tan ^{-1} x$
$\begin{array}{l}\Rightarrow \frac{\pi}{6}=\tan ^{-1} x \Rightarrow \tan \frac{\pi}{6}=x \\ \Rightarrow x=\frac{1}{\sqrt{3}}\end{array}$

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