MCQ
If $\sin ^2 x-2 \cos x+\frac{1}{4}=0$, then $x$ has value
  • A
    $2 n \pi+\frac{\pi}{4}$
  • $2 n \pi \pm \frac{\pi}{3}$
  • C
    $2 n \pi+\frac{\pi}{6}$
  • D
    $2 n \pi+\frac{\pi}{12}$

Answer

Correct option: B.
$2 n \pi \pm \frac{\pi}{3}$
(B) $\sin ^2 x-2 \cos x+\frac{1}{4}=0$
$\Rightarrow 1-\cos ^2 x-2 \cos x+\frac{1}{4}=0$
Putting $\cos x= t$, we get
$1-t^2-2 t+\frac{1}{4}=0 \Rightarrow 4 t^2+8 t-5=0$
$\therefore \quad t =\frac{1}{2}$ or $t =-\frac{5}{2}$
Since, $\cos x \neq \frac{-5}{2}$
$\therefore \cos x=\frac{1}{2}=\cos \frac{\pi}{3} \Rightarrow x=2 n \pi \pm \frac{\pi}{3}$

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