MCQ
If $\sin \theta + {\rm{cosec}}\theta = {\rm{2}}$, then ${\sin ^2}\theta + {\rm{cose}}{{\rm{c}}^{\rm{2}}}\theta = $
  • A
    $1$
  • B
    $4$
  • $2$
  • D
    None of these

Answer

Correct option: C.
$2$
c
(c) ${\sin ^2}\theta + {\rm{cose}}{{\rm{c}}^2}\theta $

$= {(\sin \theta + {\rm{cosec}}\theta )^2} - 2\sin \theta {\rm{ cosec}}\theta $

$ = {(2)^2} - 2 = 4 - 2 = 2,$

since $(\sin \theta + {\rm{cosec}}\theta ) = 2.$

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