If (x+y) = log(x+y), then dy dx = - Vidyadip

MCQ

If $\sin (x+y) = log(x+y)$, then ${{dy} \over {dx}} =$

A
$2$
B
$-2$
C
$1$
✓
$-1$

✓

Answer

Correct option: D.

$-1$

d
(d) It is implicit function, so

$\frac{{dy}}{{dx}} = - \frac{{\partial f/\partial x}}{{\partial f/\partial y}} $

$= - \frac{{\cos (x + y) - \frac{1}{{x + y}}}}{{\cos (x + y) - \frac{1}{{x + y}}}} = - 1$.

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