MCQ
If $\sin y = x\cos (a + y),$ then ${{dy} \over {dx}} = $
  • ${{{{\cos }^2}(a + y)} \over {\cos a}}$
  • B
    ${{\cos (a + y)} \over {{{\cos }^2}a}}$
  • C
    ${{{{\sin }^2}(a + y)} \over {\sin a}}$
  • D
    None of these

Answer

Correct option: A.
${{{{\cos }^2}(a + y)} \over {\cos a}}$
a
(a) $x = \frac{{\sin y}}{{\cos (a + y)}}$. 

Find $\frac{{dx}}{{dy}}$ and then $\frac{{dy}}{{dx}}$.

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