Question
If $\sin(A +B) = 1(A -B) = 1,$ find $A$ and $B.$

Answer

$\sin(A +B) = 1$
$\Rightarrow \sin(A + B) = \sin90^\circ $
$\Rightarrow A + B = 90^\circ .....(i)$
$\cos(A - B) = 1$
$\Rightarrow \cos(A - B) = \cos0^\circ $
$\Rightarrow A - B = 0^\circ ........(ii)$
Adding $(i)$ and $(ii)$
$A + B +A - B= 90^\circ + 0$
$2A = 90^\circ $
$A = 45^\circ $
Substituitng value of $A$ in $(i)$
$A + B = 90^\circ $
$45^\circ + B = 90^\circ$
$B = 45^\circ $
Therefore,
$A = B = 45^\circ .$

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