Question
Solve, using cross$-$multiplication $:\sqrt2x - \sqrt3y = 0,\sqrt5x + \sqrt2y = 0$

Answer

Given equation are $\sqrt{2 } x-\sqrt{3 } y=0$ and $\sqrt{ 5} x+\sqrt{2 } y=0$
Comparing with $\mathrm{a}_1 \mathrm{x}+\mathrm{b}_1 \mathrm{y}+\mathrm{c}_1=0$ and $\mathrm{a}_2 \mathrm{x}+\mathrm{b}_2 \mathrm{y}+\mathrm{c}_2=0$, We have
$a_1=\sqrt{2}, b_1=\sqrt{ 3} , c_1=0$ and $a_2=\sqrt{5}, b_2=\sqrt{2 } , c_2=0$
Now, $x=\frac{b_1 c_2-b_2 c_1}{a_1 b_2-a_2 b_1}$ and $y=\frac{c_1 a_2-c_2 a_1}{a_1 b_2-a_2 b_1}$
$\Rightarrow \mathrm{x}=$
$\frac{(-\sqrt{3}) \times 0-\sqrt{2} \times 0}{\sqrt{2} \times \sqrt{2}-\sqrt{5} \times(-\sqrt{3})}$ and $y=\frac{0 \times \sqrt{5}-0 \times \sqrt{2}}{\sqrt{2} \times \sqrt{2}-\sqrt{5} \times(-\sqrt{3})}$
$\Rightarrow x=\frac{0}{2+\sqrt{15}}$ and $y=\frac{0}{2+\sqrt{15}}$
$\Rightarrow x=0$ and $y=0$.

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