MCQ
If solubility of calcium hydroxide is $\sqrt 3 $, then its solubility product will be
- A$27$
- B$3$
- C$9$
- ✓$12\sqrt 3 $
${K_{sp}} = 4{S^3} = 4 \times \sqrt 3 \times \sqrt 3 \times \sqrt 3 = 12\sqrt 3 $
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$\left( 2 \right)\,{N_2}\left( g \right) + {O_2}\left( g \right) \rightleftharpoons 2NO\left( g \right)\,,\,{K_2}$
$\left( 3 \right)\,{H_2}\left( g \right) + \frac{1}{2}{O_2}\left( g \right) \rightleftharpoons {H_2}O\left( g \right)\,,\,{K_3}$
The equation for the equilibrium constart of the reaction
$2N{H_3}\left( g \right) + \frac{5}{2}{O_2}\left( g \right) \rightleftharpoons 2NO\left( g \right) + 3{H_2}O\left( g \right)$
$(K_4)$ in terms of $K_1 , K_2$ , and $K_3$ is
$\mathrm{Fe}_2 \mathrm{O}_{3(\mathrm{~s})}+3 \mathrm{CO}_{(\mathrm{g})} \rightleftharpoons \mathrm{Fe}_{(1)}+3 \mathrm{CO}_{2(\mathrm{~g})}$
Using the Le-chatelier's principle, predict which one of the following will not disturb the equilibrium.