MCQ
If $\tan ^{-1} x-\tan ^{-1} y=\tan ^{-1} A$, then $A =$
  • A
    $x-y$
  • B
    $x+y$
  • $\frac{x-y}{1+x y}$
  • D
    $\frac{x+y}{1-x y}$

Answer

Correct option: C.
$\frac{x-y}{1+x y}$
(C) $\tan ^{-1} x-\tan ^{-1} y=\tan ^{-1} A$
$\Rightarrow \tan ^{-1}\left(\frac{x-y}{1+x y}\right)=\tan ^{-1} A$
$\Rightarrow A =\frac{x-y}{1+x y}$

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