MCQ
If $\tan A = 2\tan B + \cot B,$ then $2\tan (A - B) = $
- A$\tan B$
- B$2\tan B$
- ✓$\cot B$
- D$2\cot B$
$ = 2\frac{{(2\tan B + \cot B - \tan B)}}{{1 + (2\,\tan B + \cot B)\,\tan B}} $
$= 2\,\frac{{\tan B + \cot B}}{{2\,(1 + {{\tan }^2}B)}}$
$ = \frac{{\cot B\,({{\tan }^2}B + 1)}}{{(1 + {{\tan }^2}B)}} $
$= \cot B$.
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$A = \{ \left( {a,b} \right) \in R \times R:\left| {a - 5} \right| < 1 \,\,and\,\,\left| {b - 5} \right| < 1\} $; $B = \left\{ {\left( {a,b} \right) \in R \times R:4{{\left( {a - 6} \right)}^2} + 9{{\left( {b - 5} \right)}^2} \le 36} \right\}$ then : . . . . .