MCQ
If $\tan A = \frac{1}{2},$ then $\tan 3A = $
  • A
    $\frac{9}{2}$
  • $\frac{{11}}{2}$
  • C
    $\frac{7}{2}$
  • D
    $ - \frac{1}{2}$

Answer

Correct option: B.
$\frac{{11}}{2}$
b
(b) We have $\tan A = \frac{1}{2}$

$ \Rightarrow \tan 3A = \frac{{3\tan A - {{\tan }^3}A}}{{1 - {{3+an }^2}A}} $

$= \frac{{3.\frac{1}{2} - \frac{1}{8}}}{{1 - 3.\frac{1}{4}}} $

$= \frac{{12 - 1}}{2} = \frac{{11}}{2}$.

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