MCQ
If $\tan \frac{A}{2} = \frac{3}{2},$ then $\frac{{1 + \cos A}}{{1 - \cos A}} = $
- A$ - 5$
- B$5$
- C$9/4$
- ✓$4/9$
$\frac{{1 + \cos A}}{{1 - \cos A}} $
$= \frac{{2{{\cos }^2}\frac{A}{2}}}{{2{{\sin }^2}\frac{A}{2}}} $
$= {\cot ^2}\frac{A}{2} = {\left( {\frac{2}{3}} \right)^2} = \frac{4}{9}$.
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