Question
If $\text{f(x)}=\cos\big[\pi^2\big]\text{x}+\cos\big[-\pi^2\big]\text{x},$ where[x] denotes the greatest integer less than or equal to x, then write the value of $\text{f}(\pi)$

Answer

We have, $\text{f}(\text{x})=\cos[\pi^2]\text{x}+\cos[-\pi^2]\text{x}$ $\therefore \text{f}(\pi)= \cos[\pi^2]\pi+\cos[-\pi^2]\pi$ $=0+0$ $[ \because\cos\text{n}\pi=0]$ $=0$ $\therefore\text{ f}(\pi)= 0$

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