If $\text{P(A)}=\frac{3}{10},\text{P(B)}=\frac{2}{5}$ and $\text{P}(\text{A}\cap\text{B}=\frac{3}{5,}$ then P(A|B) + P(B|A) equals
  • A$\frac{1}{4}$
  • B$\frac{7}{12}$
  • C$\frac{5}{12}$
  • D$\frac{1}{3}$
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