One ticket is drawn from a bag containing 70 tickets numbered 1 to 70 Find the probability that it is a multiple of 5 or 7:
A$\frac{1}{10}$
B$\frac{1}{70}$
C$\frac{6}{70}$
D$\frac{11}{35}$
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B$\frac{1}{70}$
Out of the 70 numbers, numbers that are a multiple of 5 or 7 are 5, 7, 10, 14, 15, 20, 21, 25, 28, 30, 35, 40, 42, 45, 49, 50, 55, 56, 60, 63, 65, 70
So, probability that the number is even $=\frac{22}{70}=\frac{22}{70}=\frac{11}{35}$
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