Question
If $\text{p(x)}= \text{x}^2-4\text{x}+3,$ evaluate: $\text{p}(2)-\text{p}(-1)+\text{p}\big(\frac{1}{2}\big).$
✓
Answer
We have $\text{p(x)}= \text{x}^2-4\text{x}+3$ $\therefore$ $\text{p}(2)-\text{p}(-1)+\text{p}\Big(\frac{1}{2}\Big)$ $=(2^2-4\times2+3)-\big\{(-1)^2-4(-1)+3\big\}+\Big\{\Big(\frac{1}{2}\Big)^2-4\times\frac{1}{2}+3\Big\}$ $=(4-8+3)-(1+4+3)+\Big(\frac{1}{4}-2+3\Big)$ $=-1-8+\frac{5}{4}$ $=-9+\frac{5}{4}=\frac{-36+5}{4}=\frac{-31}{4}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In which quadrant will the point lie, if:
(i) The y-coordinate is 3 and the x-coordinate is -4?
(ii) The x-coordinate is -5 and the y-coordinate is-3?
(iii) The y-coordinate is 4 and the x-coordinate is 5?
(iv) The y-coordinate is 4 and the x-coordinate is -4?
(i) The y-coordinate is 3 and the x-coordinate is -4?
(ii) The x-coordinate is -5 and the y-coordinate is-3?
(iii) The y-coordinate is 4 and the x-coordinate is 5?
(iv) The y-coordinate is 4 and the x-coordinate is -4?
Simplify: $\Big(\frac{7776}{243}\Big)^{-\frac{3}{5}}$
→In the given figure, $\angle PQR =\angle PRQ$, then prove that $\angle PQS =\angle PRT$
→Expand the following:
$(3 a-5 b-c)^2$
→$(3 a-5 b-c)^2$
Write the following in decimal form and say what kind of decimal expansion has. $2\frac{5}{12}$
→Factorise:
$a^2-b^2+2 b c-c^2$
→$a^2-b^2+2 b c-c^2$
Solve the following equations for $x:$
$2^{\text{x}+1}=4^{\text{x}-3}$
→$2^{\text{x}+1}=4^{\text{x}-3}$
What must be subtracted from $x^3 - 6x^2 - 15x + 80$ so that the result is exactly divisible by $x^2 + x - 12?$
→ Find the following products:
$\Big(\frac{\text{x}}{2}+2\text{y}\Big)\Big(\frac{\text{x}^2}{4}-\text{xy}+4\text{y}^2\Big)$
→$\Big(\frac{\text{x}}{2}+2\text{y}\Big)\Big(\frac{\text{x}^2}{4}-\text{xy}+4\text{y}^2\Big)$
Examine whether the following numbers are rational or irrational. $\sqrt{\frac{13}{117}}$
→