MCQ
If $(\text{x}-\frac{1}{\text{x}})^2=\text{x}^2+\text{a}+\frac{1}{\text{x}^2}$ then a =
- ✓$-2$
- B$2$
- C$2x$
- D$-2x$
✓
Answer
Correct option: A.
$-2$
$(\text{x}-\frac{1}{\text{x}})^2=\text{x}^2-2+\frac{1}{\text{x}^2}$
$\therefore\text{a}=-2$
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