MCQ
If $\frac{\text{x}}{2}-4=\frac{\text{x}}{3}-1,$ then $x =$
- A$3$
- B$6$
- ✓$18$
- D$2$
✓
Answer
Correct option: C.
$18$
As, $\frac{\text{x}}{2}-4=\frac{\text{x}}{3}-1$
$\Rightarrow\frac{\text{x}}{2}-\frac{\text{x}}{3}=4-1$ (By transposing $\frac{\text{x}}{3}$ to $L.H.S.$ and $-4$ to $R.H.S.)$
$\Rightarrow\frac{3\text{x}}{6}-\frac{2\text{x}}{6}=3$
$\Rightarrow\frac{3\text{x}-2\text{x}}{6}=3$
$\Rightarrow\frac{\text{x}}{6}=3$
$\Rightarrow\text{x}=3\times6 ($By transposing $6$ to $R.H.S.)$
$\therefore\text{x}=18$
Hence, the correct alternative is option $(c).$
$\Rightarrow\frac{\text{x}}{2}-\frac{\text{x}}{3}=4-1$ (By transposing $\frac{\text{x}}{3}$ to $L.H.S.$ and $-4$ to $R.H.S.)$
$\Rightarrow\frac{3\text{x}}{6}-\frac{2\text{x}}{6}=3$
$\Rightarrow\frac{3\text{x}-2\text{x}}{6}=3$
$\Rightarrow\frac{\text{x}}{6}=3$
$\Rightarrow\text{x}=3\times6 ($By transposing $6$ to $R.H.S.)$
$\therefore\text{x}=18$
Hence, the correct alternative is option $(c).$
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