MCQ
If $\text{x}\tan45^\circ\cos60^\circ=\sin60^\circ\cot60^\circ$ then $\text{x}=?$
- ✓$1$
- B$\frac{1}{2}$
- C$\frac{1}{\sqrt2}$
- D$\sqrt3$
✓
Answer
Correct option: A.
$1$
$\text{x}\tan45^\circ\cos60^\circ=\sin60^\circ\cot60^\circ$
$\Rightarrow\text{x}\times1\times\frac{1}{2}$
$=\frac{\sqrt3}{2}\times\frac{1}{\sqrt3}$
$\Rightarrow\frac{\text{x}}2{}=\frac{1}{2}$
$\Rightarrow\text{x}=1$
$\Rightarrow\text{x}\times1\times\frac{1}{2}$
$=\frac{\sqrt3}{2}\times\frac{1}{\sqrt3}$
$\Rightarrow\frac{\text{x}}2{}=\frac{1}{2}$
$\Rightarrow\text{x}=1$
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