MCQ
If $\frac {\text{x}}{\text{y}} = \frac {6}{5} $ then $ \frac {\text{x}^{2} +\text{ y}^{2}}{\text{x}^{2} - \text{y}^{2}}$ is:
- A$\frac {36}{25}$
- B$\frac {25}{36}$
- ✓$\frac {61}{11}$
- D$\frac {11}{61}$
Given that, $\frac{\text{x}}{\text{y}} = \frac{6}{5} $
$\Rightarrow \text{x} = \frac{6\text{y}}{5}$
To find, $ \frac{\text{x}^{2}+\text{y}^{2}}{\text{x}^{2}-\text{y}^{2}}$ .
Substituting value of $x$ in this,
we get $\therefore \frac {\frac{36\text{y}^{2}}{25} + \text{y}^{2}}{\frac{36\text{y}^{2}}{25} - \text{y}^{2}} = \frac{61\text{y}^{2}}{11\text{y}^{2}} = \frac{61}{11}$
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