MCQ
If the bond dissociation energies of $XY,\,{X_2}$ and ${Y_2}$ (all diatomic molecules) are in the ratio of $1 : 1 : 0.5 $ and ${\Delta _f}H$ for the formation of $XY$ is $ - 200\,kJ\,mol{e^{ - 1}}$. The bond dissociation energy of ${X_2}$ will be.....$kJ\,mo{l^{ - 1}}$
  • A
    $100$
  • $800$
  • C
    $300$
  • D
    $400$

Answer

Correct option: B.
$800$
(b)$XY\xrightarrow{{}}{X_{(g)}} + {Y_{(g)}}$  $\Delta H =  + a\,\,kJ/mole$   ……….$(i)$

${X_2}\xrightarrow{{}}2X$; $\Delta H =  + a\,\,kJ/mole$                              ………. $(ii)$

 ${Y_2}\xrightarrow{{}}2Y$;  $\Delta H =  + 0.5\,a\,\,kJ/mole$                        ……….$(iii)$

$\frac{1}{2} \times {\text{(ii) }} + \frac{{\text{1}}}{{\text{2}}} \times {\text{(iii) - (i),}}$  gives 

$\Delta H = \left( { + \frac{a}{2} + \frac{{0.5}}{2}a - a} \right)\,\,kJ/mole$
$ + \frac{a}{2} + \frac{{0.5a}}{2} - a = - 200$
$a = 800$

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