Question
If the complement of an angle is $62^\circ ,$ then find its supplement.
✓
Answer
Let the angle be $x^\circ .$
We know that, sum of two complementary angles is $90^\circ .$
$\therefore x + 62^\circ = 90^\circ $
$ \Rightarrow x = 90^\circ - 62^\circ = 28^\circ $
Supplemant of angle is $(180^\circ \ -$ angle$).$
$\therefore$ Supplemant of $x + 180^\circ - 28^\circ = 152^\circ $
We know that, sum of two complementary angles is $90^\circ .$
$\therefore x + 62^\circ = 90^\circ $
$ \Rightarrow x = 90^\circ - 62^\circ = 28^\circ $
Supplemant of angle is $(180^\circ \ -$ angle$).$
$\therefore$ Supplemant of $x + 180^\circ - 28^\circ = 152^\circ $
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