Find 1 2 of (a) 2 3 4 (b) 4 2 9

Question

Find
$\frac{1}{2}$ of$\quad$(a) $2 \frac{3}{4}$ (b) $4 \frac{2}{9}$

✓

Answer

(a) We have, $\frac{1}{2}$ of $2 \frac{3}{4}=\frac{1}{2} \times 2 \frac{3}{4}$
$
\begin{array}{l}
=\frac{1}{2} \times\left(\frac{2 \times 4+3}{4}\right) \\
=\frac{1}{2} \times\left(\frac{8+3}{4}\right) \\
=\frac{1}{2} \times \frac{11}{4}=\frac{11}{8}=1 \frac{3}{8}
\end{array}
$
(b) We have, $\frac{1}{2}$ of $4 \frac{2}{9}=\frac{1}{2} \times 4 \frac{2}{9}$
$
\begin{array}{l}
=\frac{1}{2} \times\left(\frac{4 \times 9+2}{9}\right) \\
=\frac{1}{2} \times\left(\frac{36+2}{9}\right) \\
=\frac{1}{2} \times \frac{38}{9}=\frac{1 \times 19}{1 \times 9}
\end{array}
$
[dividing numerator and denominator by 2 ]
$
=\frac{19}{9}=2 \frac{1}{9}
$

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