MCQ
If the coordinates of a point be given by the equations $x = b\sec \phi ,\;\;y = a\tan \phi $, then its locus is
- AA straight line
- BA circle
- CAn ellipse
- ✓A hyperbola
Therefore $\frac{{{x^2}}}{{{b^2}}} - \frac{{{y^2}}}{{{a^2}}} = {\sec ^2}\phi - {\tan ^2}\phi \,\,$
$\Rightarrow \,\,\frac{{{x^2}}}{{{b^2}}} - \frac{{{y^2}}}{{{a^2}}} = 1$,
which is obviously a hyperbola.
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