MCQ
If the eccentricity of the two ellipse $\frac{{{x^2}}}{{169}} + \frac{{{y^2}}}{{25}} = 1$ and $\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1$ are equal, then the value of $a/b$ is
- A$5\over{13}$
- B$6\over{13}$
- ✓$13\over5$
- D$13\over6$
In the second case, $e'\, = \sqrt {1 - ({b^2}/{a^2})} $
According to the given condition,
$\sqrt {1 - {b^2}/{a^2}} = \sqrt {1 - (25/169)} $
$ \Rightarrow \,b/a = 5/13$, $(\because \,\,a > 0,\,b > 0)$
$⇒ a/b = 13/5.$
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