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CONIC SECTIONS — MATHS STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceMATHSCONIC SECTIONS1 Mark
MCQ
If the equation $\frac{\lambda(\text{x}+1)^2}{3}+\frac{(\text{y}+2)^2}{4}=1$ represents a circle then $\lambda$:
  • A
    $1$
  • ✓
    $\frac{3}{4}$
  • C
    $0$
  • D
    $-\frac{3}{4}$
✓

Answer

Correct option: B.
$\frac{3}{4}$
  1. $\frac{3}{4}$
Solution:
$\frac{\lambda(\text{x}+1)^2}{3}+\frac{(\text{y}+2)^2}{4}=1$
for a circle of a $(\text{x}-\alpha)^2+6 (\text{y}-\beta)^2=1$ then (a = 6)
$\frac{\lambda}{3}=\frac{1}{4}$
$\lambda=\frac{3}{4}$

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