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6.1. Equilibrium - 1 (chemical Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.1. Equilibrium - 1 (chemical Equilibrium)1 Mark
MCQ
If the equilibrium constant for $A \rightleftharpoons B+C$ is $K _{ eq }^{(1)}$ and that of $B + C \rightleftharpoons P \quad$ is $K _{ eq }^{(2)},$ the equilibrium constant for $A \rightleftharpoons P$ is :-
  • A
    $K _{ eq }^{(2)}- K _{ eq }^{(1)}$
  • ✓
    $K _{ eq }^{(1)} K _{ eq }^{(2)}$
  • C
    $K _{ eq }^{(1)} / K _{ eq }^{(2)}$
  • D
    $K _{ eq }^{(1)}+ K _{ eq }^{(2)}$
✓

Answer

Correct option: B.
$K _{ eq }^{(1)} K _{ eq }^{(2)}$
b
$A \rightleftharpoons B+C \quad K_{e q}^{(1)}=\frac{[B][C]}{[A]}$$.....(1)$

$B + C \rightleftharpoons P \quad K _{ eq }^{(2)}=\frac{[ P ]}{[ B ][ C ]}$$.....(2)$

For

$A \rightleftharpoons P \quad K_{e q}=\frac{[P]}{[A]}$

Multiplying equation $(1)$ $\&$ $(2)$

$K _{ eq }^{( l )} \times K _{ eq }^{(2)}=\frac{[ P ]}{[ A ]}= K _{ eq }$

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