Question
If the events $A$ and $B$ are mutually exclusive, then $P\left( {\frac{A}{B}} \right) = $
Since $A$ and $B$ are mutually exclusive.
So, $P(A \cap B) = 0$.
Hence $P\left( {\frac{A}{B}} \right) = \frac{0}{{P(B)}} = 0$.
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