MCQ
If the function $f : R \rightarrow R$ be given by $ \text{f}(\text{x}) = \text{x}^2 + 2$ and $g : R \rightarrow R$ is given by $\text{g}(\text{x})=\frac{\text{x}}{\text{ x - 1}}$ The value of $gof(x)$ is.
  • $ \frac{(\text{x}^{2} + 2)}{(\text{x}^{2} + 1)}$
  • B
    $ \frac{\text{x}^{2}}{(\text{x}^{2} + 1)}$
  • C
    $ \frac{\text{x}^{ 2}}{(\text{x}^{2} + 2)}$
  • D
    $ \text{None of these}$

Answer

Correct option: A.
$ \frac{(\text{x}^{2} + 2)}{(\text{x}^{2} + 1)}$
Given $ \text{f}(\text{x}) = \text{x}^2 + 2$ and $\text{gof}(\text{x}) =\text{g}(\text{x}^{2} - 1)$
Now, $\text{gof}(\text{x}) =\text{g}(\text{x}^{2} + 2)$
$ = \frac{(\text{x}^{2} + 2)}{(\text{x}^{2} + 2 – 1)}$
$ = \frac{(\text{x}^{2} + 2)}{(\text{x}^{2} + 1)}$

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