MCQ
If the function $f(x)=\left\{\begin{array}{cl}\frac{1}{|x|} & ,|x| \geq 2 \\ a x^2+2 b, & |x|<2\end{array}\right.$ is differentiable on $R$, then $48(a+b)$ is equal to___________.
  • $15$
  • B
    $16$
  • C
    $75$
  • D
    $78$

Answer

Correct option: A.
$15$
a
$f(x)\left\{\begin{array}{c}\frac{1}{\mathrm{x}} ; \mathrm{x} \geq 2 \\ \mathrm{ax}^2+2 \mathrm{~b} ;-2<\mathrm{x}<2 \\ -\frac{1}{\mathrm{x}} ; \mathrm{x} \leq-2\end{array}\right.$

Continuous at $\mathrm{x}=2 \quad \Rightarrow \frac{1}{2}=\frac{\mathrm{a}}{4}+2 \mathrm{~b}$

Continuous at $\mathrm{x}=-2 \quad \Rightarrow \frac{1}{2}=\frac{\mathrm{a}}{4}+2 \mathrm{~b}$

Since, it is differentiable at $\mathrm{x}=2$

$-\frac{1}{x^2}=2 a x$

Differentiable at $x=2 \quad \Rightarrow \frac{-1}{4}=4 a \Rightarrow a=\frac{-1}{16}, b$

$=\frac{3}{8}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Let $A = \,\left[ {\begin{array}{*{20}{c}}
1&0&0\\
1&1&0\\
1&1&1
\end{array}} \right]$ and $B = A^{20}$ . Then the sum of the elements of the first column of $B$ is?
If the length of a vector be $21$ and direction ratios be $2, -3, 6$ then its direction cosines are
Solution of the differential equation $y' = y\tan x - 2\sin x,$ is
If abscissa of vertex of parabola $y = a{x^2} + bx + c$ is $1\left( {a,b,c > 0} \right)$ and $f(x) = \int\limits_0^x {\left( {3a{x^2} + bx + c} \right)dx} $ is strictly increasing function $\forall \,\,\,x\, \in \,R$ , then maximum possible value of $\left[ {\frac{a}{c}} \right]$ is (where [.] denotes greatest integer function)
The projection of any line on co-ordinate axes be respectively $3, 4, 5$ then its length is
The area (in sq. units) enclosed between the graph of y = x3 and the lines x = 0, y = 1, y = 8 is:
  1. $\frac{45}{4}$
  2. $14$
  3. $7$
  4. $\text{ none of these}$
$\int_{}^{} {\frac{{{e^{\sqrt x }}\cos {e^{\sqrt x }}}}{{\sqrt x }}dx} = $
Let $\mathrm{f}(\mathrm{x})$ be a polynomial of degree $3$ such that $\mathrm{f}(\mathrm{k})=-\frac{2}{\mathrm{k}}$ for $\mathrm{k}=2,3,4,5 .$ Then the value of $52-10 \mathrm{f}(10)$ is equal to :
If $\text{f(x)}=|\log_{10}\text{x}|\text{fx}=\log_{10}\text{x},$ then at x = 1:
  1. f(x) is continuous and $\text{f}'(1^+)=\log_{10}\text{e}$
  2. f(x) is continuous and $\text{f}'(1^+)=\log_{10}\text{e}$
  3. f(x) is continuous and $\text{f}'(1^-)=-\log_{10}\text{e}$
  4. f(x) is continuous and $\text{f}'(1^-)=-\log_{10}\text{e}$
The number of solutions of $\frac{d y}{d x}=\frac{y+1}{x-1}$, when $y(1)=2$ is