$f \left(\pi^{-}\right)= f (\pi)= f \left(\pi^{+}\right)$
$-1=-k_{2}$
$k _{2}=1$
$f^{\prime}(x)=\left\{\begin{array}{l}2 k_{1}(x-\pi) ; x \leq \pi \\ -k_{2} \sin x \quad ; x>\pi\end{array}\right.$
$f^{\prime}\left(\pi^{-}\right)=f^{\prime}\left(\pi^{+}\right)$
$0=0$
so, differentiable at $x=0$
$f ^{\prime \prime}( x )=\left\{\begin{array}{cc}2 k _{1} & ; x \leq \pi \\ - k _{2} \cos x ; x >\pi\end{array}\right.$
$f ^{\prime \prime}\left(\pi^{-}\right)= f ^{\prime \prime}\left(\pi^{+}\right)$
$2 k _{1}= k _{2}$
$k_{1}=\frac{1}{2}$
$\left( k _{1}, k _{2}\right)=\left(\frac{1}{2}, 1\right)$
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$l_1: \overrightarrow{ r }=(\hat{ i }-11 \hat{ j }-7 \hat{ k })+\lambda(\hat{ i }+2 \hat{ j }+3 \hat{ k }), \lambda \in R$
and $l_2: \overrightarrow{ r }=(-\hat{ i }+\hat{ k })+\mu(2 \hat{ i }+2 \hat{ j }+\hat{ k }), \mu \in R$.
If $P$ is the point of intersection of $l$ and $l_1$, and $Q (\alpha$ $, \beta, \gamma)$ is the foot of perpendicular from $P$ on $l_2$, then $9(\alpha+\beta+\gamma)$ is equal to $..........$.