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Relations and Functions — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsRelations and Functions2 Marks
Question
If the function t which maps temperature in degree Celcius into temperature in degree Fahrenheit is defined by t(C) = $\frac{9C}{5}$+ 32, then find the value of C, when t(C) = 212.
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Answer

Here it is given that, $t(C) =$ $\frac{9 C}{5}$$+ 32$
Put $t(C) = 212$, we get
$212 =$ $\frac{9 C}{5}$ + 32
$\Rightarrow$ $\frac{9 C}{5}$$= 212 - 32$
$\Rightarrow$ $\frac{9 C}{5}$ = 180
$\therefore$ C = $\frac{5 \times 180}{9}$
$C = 5$ $\times$ 20 = 100

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