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Relations and Functions — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsRelations and Functions2 Marks
Question
If the function t which maps temperature in degree Celcius into temperature in degree Fahrenheit is defined by t(C) = $\frac{9C}{5}$+ 32, then find t(-10).
✓

Answer

Here it is given that, $t(C) =$ $\frac{9 C}{5}$$+ 32$
Put C = -10, we get
$t(-10) =$ $\frac{9 \times(-10)}{5}$$+ 32$
= $\frac{-9 \times 10}{5}$ $+ 32 = - 9$ $\times$ $2 + 32$
= -18 + 32 = 14

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