If the length of a closed organ pipe is $1m $ and velocity of sound is $330 m/s$, then the frequency for the second note is
  • A$4 \times \frac{{330}}{4}Hz$
  • B$3 \times \frac{{330}}{4}Hz$
  • C$2 \times \frac{{330}}{4}Hz$
  • D$2 \times \frac{4}{{330}}Hz$
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