If the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is $\frac{x}{2}$ times its original time period. Then the value of $x$ is:
  • A$\sqrt{2}$
  • B$2 \sqrt{3}$
  • C$4$
  • D$\sqrt{3}$
NEET 2024, Medium
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