- A0
- Ba2
- C2a2
- D4a2
Explanation:
Path difference at the central fringe will be the same as the path difference at the slits i.e. $\lambda$.
Hence, the waves reaching the central fringe will be 180° out of phase and will result in destructive interference. Hence, the intensity of the central fringe will be 0.
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Minimum excitation potential of Bohr's first orbit in hydrogen atom is
|
(a) 13.6 V |
(b) 3.4 V |
(c) 10.2 V |
(d) 3.6 V |
The figure shows a network of currents. The magnitude of currents is shown here. The current i will be
|
(a) 3 A |
(b) 13 A |
(c) 23 A |
(d) – 3 A |
Three capacitances of capacity 10 μF, 5 μF and 5 μF are connected in parallel. The total capacity will be
|
(a) 10 μF |
(b) 5 μF |
(c) 20 μF |
(d) None of the above |