MCQ
If the $pH$ of a solution is $ 2$, its normality will be
- A$2$
- B$0.5$
- ✓$0.01$
- DNone of these
✓
Answer
Correct option: C.
$0.01$
(c) $pH = 2$ ; $pH = - \log \,\,[{H^ + }]$ ; $2 = - \log \,\,\,[{H^ + }]$
$[{H^ + }] = {10^{ - 2}} = 0.01\,N$
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