MCQ
The hydrocarbon which can react with sodium in liquid ammonia is ____________________ .
  • A
    $CH _3 CH = CHCH _3$
  • $CH _3 CH _2 C \equiv CH$
  • C
    $CH _3 CH _2 CH _2 C \equiv CCH _2 CH _2 CH _3$
  • D
    $CH _3 CH _2 C \equiv CCH _2 CH _3$

Answer

Correct option: B.
$CH _3 CH _2 C \equiv CH$
(b) $CH _3 CH _2 C \equiv CH$
Explanation: Terminal alkynes react with Na in the presence of liquid $NH _3$ to form higher alkynes. The alkyne contains acidic H at the end (i.e. the H bonded to $C _1$ of the chain). Therefore, it is easily replaced with highly electropositive metals such as Na in liquid ammonia, to form sodium alkaline ion which can react further in the presence of a suitable catalyst to yield higher alkynes/hydrocarbons.

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