MCQ
If the points $( - 5,\,1),\,(p,\,5)$ and $(10,\,7)$ are collinear, then the value of $p$ will be
- ✓$5$
- B$3$
- C$4$
- D$7$
$\Rightarrow \,\,\left| {\,\begin{array}{*{20}{c}}{ - 5}&1&1\\p&5&1\\{10}&7&1\end{array}\,} \right| = \,0\,$
$ \Rightarrow \,\,10 - (p - 10) + (7p - 50) = 0\,\,$
$\Rightarrow \,\,p = 5$.
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