MCQ
If the points $(a,b),\,(a',b')$and $(a - a',b - b')$are collinear, then
- ✓$ab' = a'b$
- B$ab = a'b'$
- C$aa' = bb'$
- D${a^2} + {b^2} = 1$
$ \Rightarrow \,\,\,\frac{{a - 2a'}}{{a' - a}} = \frac{{b - 2b'}}{{b' - b}}$
$ \Rightarrow \,\,\frac{a}{{a'}} = \frac{b}{{b'}}\,\,$
$\Rightarrow \,\,ab' = a'b.$
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