Question
If the radius of earth shrinks by $2 \%$ while its mass remains same. The acceleration due to gravity on the earth's surface will approximately.

Answer

$g=\frac{G M}{R^{2}}$

$M =$ constant $g<\frac{1}{ R ^{2}}$

$100 \frac{\Delta g}{g}=-2 \frac{\Delta R}{R} 100$

$\%$ change $=-2(-2)$

$\%$ change in $g =4 \%$

increase by $4 \%$

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