MCQ
If the ratio of cross-sections of a tube of unequal radius at two places is $1: 2$, then for an in compressible fluid the ratio of the velocities of the fluid entering and exiting the tube will be :
- A1 : 2
- ✓2 : 1
- C1 : 4
- D1 : 1
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Statement $-2$: Maximum energy loss occurs when the particles get stuck together as a result of the collision.


[Figure shows position of reference $'O'$ when jaws of screw gauge are closed]
Given pitch $=0.1 \,{cm}$.