Question
If the reading of the ammeter, $A_1$ in the figure. is 2.4A, what will be the readings of ammeters $A_2$ and $A_3$? Neglect the resistances of the ammeters.
✓
Answer
$A_1 = 2.4A$
Since $A_1$ and $A_2$ are in parallel,$\Rightarrow20\times2.4=30\times\text{X}$
$\Rightarrow\text{x}=\frac{20\times2.4}{30}=1.6\text{A}.$
Reading in Ammeter $A_2$ is 1.6A.$\text{A}_3=\text{A}_1+\text{A}_2=2.4+1.6=4.0\text{A}.$
Since $A_1$ and $A_2$ are in parallel,$\Rightarrow20\times2.4=30\times\text{X}$
$\Rightarrow\text{x}=\frac{20\times2.4}{30}=1.6\text{A}.$
Reading in Ammeter $A_2$ is 1.6A.$\text{A}_3=\text{A}_1+\text{A}_2=2.4+1.6=4.0\text{A}.$
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