MCQ
If the solution boils at a temperature ${T_1}$ and the solvent at a temperature ${T_2}$ the elevation of boiling point is given by
- A${T_1} + {T_2}$
- ✓${T_1} - {T_2}$
- C${T_2} - {T_1}$
- D${T_1} \div {T_2}$
The reason is after adding non-volatile solute the boiling point of the solution will increase.
Vapour pressure of the solution at some temperature is found to be lower than the vapour pressure of the pure solvent at the same temperature. In such a solution, the nonvolatile solute particles will obstruct the escaping of solvent molecules from the surface.
Therefore, it reduces the vapour pressure. Due to this, Elevation in the boiling point is based on the colligative property.
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Which combination gives the highest yield of $z,$ at equilibrium.
Statement $I$ : The electronegativity of group $14$ elements from $\mathrm{Si}$ to $\mathrm{Pb}$ gradually decreases.
Statement $II$ : Group $14$ contains non-metallic, metallic, as well as metalloid elements.
In the light of the above statements, choose the most appropriate from the options given below :
$(I)\, Co(III)$ is stabilised in presence of weak field ligands, while $Co(II)$ is stabilised in presence of strong field ligand.
$(II)$ Four coordinated complexes of $Pd(II)$ and $Pt(II)$ are diamagnetic and square planar.
$(III)\,[Ni (CN)_4]^{4-}$ ion and $[Ni (CO)_4]$ are diamagnetic tetrahedral and square planar respectively.
$(IV)\,Ni^{2+}$ ion does not form inner orbital octahedral complexes.
$[i.e.\, \Lambda ^o_{m(NH_4OH)}]$ is equal to