Question
If the temperature of a substance is $-50^{\circ}\text C $ centigrade scale, then find its tempeature on (i) Fahrenheit and (ii) Kelvin scale.

Answer

We know that
$\begin{aligned} \frac{ T _{ C }}{100} & =\frac{ T _{ F }-32}{180} \\ \frac{-50}{5} & =\frac{ T _{ F }-32}{9} \\\therefore~ T_{ F } & =\frac{-50 \times 9}{5}+32 \\ T_{ F } & =-90+32=-58^{\circ} F \end{aligned}$
(ii) $\frac{ T _c}{100}=\frac{ T _{ K }-273}{373-273}$
$\begin{aligned} \frac{ T _{ C }}{100} & =\frac{ T _{ K }-273}{100} \\ T_{ K } & = T _{ C }+273 \\ & =-58^{\circ} C +273=215 K\end{aligned}$

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