MCQ
If the TSA of a solid hemisphere is $12\pi\text{ sq.cm}$ then its CSA is:
- A$2\pi\text{ sq.cm}$
- B$12\pi\text{ sq.cm}$
- C$8\pi\text{ sq.cm}$
- D$16\pi\text{ sq.cm}$
✓
Answer
- $8\pi\text{ sq.cm}$
Solution:
Given: TSA of solid hemisphere $=12\pi\text{ sq.cm}$
$\Rightarrow3\pi\text{r}^2=12\pi$
$\Rightarrow\text{r}^2=4$
$\Rightarrow\text{r}=2\text{cm}$
$\therefore$ CSA of hemisphere $=2\pi\text{r}^2=2\pi(2)^2=8\pi\text{ sq.cm}$
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